calculate the no of atoms present in 50 grams of caco3
Answers
Answered by
128
Given mass = 50 g
Molecular weight of CaCO3 = 100 g / mol
No. of moles (n) = Given mass (m) / Molecular weight (M)
n = 50 / 100
n = 1 / 2
n = 0.5
No. of molecules = n * 6.022 * 10²³
= 0.5 * 6.022 * 10²³
= 3.011 * 10²³
No. of atoms = 5 * 3.011 * 10²³
= 15.055 * 10²³
Molecular weight of CaCO3 = 100 g / mol
No. of moles (n) = Given mass (m) / Molecular weight (M)
n = 50 / 100
n = 1 / 2
n = 0.5
No. of molecules = n * 6.022 * 10²³
= 0.5 * 6.022 * 10²³
= 3.011 * 10²³
No. of atoms = 5 * 3.011 * 10²³
= 15.055 * 10²³
abhi178:
please check again
Answered by
54
molecular weight of CaCO3 = 100 g
we know,
mole = given weight/molecular weight
= 50g/100g = 1/2
also ,
no of molecules = mole x 6.023 x 10^23
=1/2 x 6.023 x 10^23
= 3.0115 x 10^23
now, no of atoms = 5 x no of molecules
=5 x 3.0115 x 10^23
=15.0575 x 10^23
we know,
mole = given weight/molecular weight
= 50g/100g = 1/2
also ,
no of molecules = mole x 6.023 x 10^23
=1/2 x 6.023 x 10^23
= 3.0115 x 10^23
now, no of atoms = 5 x no of molecules
=5 x 3.0115 x 10^23
=15.0575 x 10^23
have you understand
but the power should be 22
yes you can also write this 1
150.575 x 10^22
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