Calculate the no. Of electrons constituting 1c of charge
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charge on one electron is 1.9×10^(_19) C
then 1/*1 6×10(_19) = 6.25 ×10^18 is no of electrons in one c
then 1/*1 6×10(_19) = 6.25 ×10^18 is no of electrons in one c
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Heya user !!
Here is your answer !!
Charge of 1 electron = 1.6 × 10^-19 C
Therefore , no. of electrons constituting 1 C of charge
= 1 C / 1.6 × 10^-19 C
= 6.25 × 10^18 electrons .
Hope it helps !!
Here is your answer !!
Charge of 1 electron = 1.6 × 10^-19 C
Therefore , no. of electrons constituting 1 C of charge
= 1 C / 1.6 × 10^-19 C
= 6.25 × 10^18 electrons .
Hope it helps !!
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