Question

calculate the no of electrons in 3600 g of glucose​

Answer 1

Answer:

Mass of glucose =1.80gm

Molecular mass of glucose (C

6

H

12

O

6

)=180gm

No. of moles =

180

1.80

=10

−2

moles

Number of molecules of glucose=10

−2

×6.023×10

23

=6.023×10

21

molecules of C

6

H

12

O

6

Total number of oxygen atoms present in glucose =6×6.023×10

21

Number of moles of water =

18g

36g

=2 moles

Number of H

2

O molecules =2×6.023×10

23

H

2

O molecules.

Therefore, no. of oxygen atoms in water =12.046×10

23

Total number of oxygen atoms present in solution (water+glucose),

12.046×10

23

+36.138×10

21

=12.406×10

23

oxygen atoms

Answer 2

Explanation:

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