Question

Calculate the no of electrons present in 4.4 gram of CO2

Answer 1

total moles is 0.1 moles of Co2
now total molecules is NA/10
as we know 1 Co2 molecule contain 6+2*8 = 22 electrons
then total no. of electrons will be NA/10 * 22= 2.2NA

Answer 2

Answer: $13.25\times 10^{23}$

Explanation:

Moles is calculated by using the formula:

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of $CO_2$ = 4.4 g

${\text {Moles of hydrogen}}=\frac{4.4g}{44g/mol}=0.1moles$

1 atom of carbon $(C)$ contains= 6 electrons

1 atom of oxygen $(O)$ contains = 8 electrons

1 mole of $CO_2$ contains $6.023\times 10^{23}$ atoms of carbon  $(C)$ and  $2\times 6.023\times 10^{23}=12.05\times 10^{23}$ atoms of oxygen.

Thus 1 mole of carbon $(C)$ contains= $6\times 6.023\times 10^{23}=36.14\times 10^{23}$ electrons.

Thus 1 mole of oxygen $(O)$ contains= $8\times 12.05\times 10^{23}=96.4\times 10^{23}$ electrons.

Thus total number of electrons in 1 mole of $CO_2=36.14\times 10^{23}+96.4\times 10^{23}=132.54\times 10^{23}$ electrons

0.1 mole of $CO_2$ contains =$\frac{132.54\times 10^{23}}{1}\times 0.1=13.25\times 10^{23}$ electrons.