Question

calculate the no.of electrons, protons and neutrons in 48 g of sulphate ion.​

Answer 1

Answer:. If an ion contains 50 protons,68 neutrons and 48 electrons.

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Answer 2

Answer:

In sulphate ion, number of electrons = 50

Number of protons = 48

Number of neutrons = 48

Explanation:

Electrons in Sulphate ion $SO_{4}^{2-}$ = 16 (from S atom ) + 8×4( from O atom) +2(due to presence of -2 charge)

Number of electrons $= 16(1)+4(8)+2$

                                  $=16+32+2\\=50$

Number of protons $SO_{4}^{2-}$ = 16 ( in P) +  8×4( in O atom)

                                         $=16+32=48$

Number of neutrons, $SO_{4}^{2-}$ $=(32-16)+4(16-8)$

                                           $=16+32=48$

In $SO_{4}^{2-}$ number of electrons, protons and neutrons are 50, 48, 48 respectively.