Question

Calculate the no. Of electrons , protons and nuetrons in phosphate ion . Mass numbers p=31 o = 16 and atomic numbers p=15 and o=8

Answer 1

chemical formual of phosphate is PO4^-3.

for no of proton= atomic no of phosphorus+4* atomic no. of oxygen

= 15+4*8= 47

for no of neutron

mass of phosphorus - atomic no of phosphorus + 4*( mass of oxygen - atomic no of oxygen)

=31-15+4*(16-8)

=16+32= 48.

for no of electron

find valancy of atoms

we know here oxy is in -2

tolat minus charge is 4*(-2)=-8

ans overall charge on phosphate is minus 3 so chare on phosphorus is over all charge - total charge on oxygen =(-3-(-8))=5

so no of electron od phosphorus =15-5=10

in oxygen 4*(8+2) =40

total no of electron is 50

alternate method for elctron

is

add atomic no. of every atom - charge on whole molecule(with sign)

15+4*8-(-3)=50

Answer 2

Answer:

the answer is 50,47,48 please mark me as brainliest