Question

calculate the no of grams of oxygen in 0.10 mole of Na2CO3.10H2O

Answer 1

Calculate no.of atoms of oxygen in 1 Mole of Na2CO3*10H2O.

Oxygen has molar mass of 16.

Oxygen amount in Na2CO3.10H2O is 10 O+ 3 O

13 Oxygen atoms.

13*16= 208.

So 1 Mole of Na2CO3.10H2O has 208 gms of oxygen atoms. But 0.1 Mole has 20.8 gms of oxygen

FYI Not needed in case if you need have a look.

Calculate Na2CO3*10H2O molar weight

Na (sodium ) has molar mass of 23.

C (carbon) has molar mass 12

O(oxygen) has 16 and hydrogen(H) has 1.

Now calculate molar mass =

23*2+ 12+ 3*16 + 10(1*2+ 16)

= 46+12+48+180

=286 is molar mass of Na2CO3.10H2O.

Answer 2

Explanation:

1Answer :

1 mole of Na2CO3. 10H2O contains 13 moles of oxygen atoms.

0.1 mole Na2CO3. 10H2O contains 13 × 0.1 = 1.3 moles of oxygen atoms.

Mass of oxygen atoms = 1.3 × 16 = 30.8g