Question

calculate the no of homozygous dominant plant if the no of homozygous recessive plant is 360 out of 1000​

Answer 1

Answer:

160

Explanation:

q^2= 360 out of 1000 individuals

q^2=360/1000

q=0.6

p+q=1

p=1-0.6=0.4

p^2 = 0.16

no.of homozygous dominant (AA) = 0.16 * 1000 = 160

hope it helps .........

Answer 2

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The frequency of the recessive allele.

Since we believe that the homozygous recessive for this gene (q2) represents 4% (i.e. = 0.04), the square root (q) is 0.2 (20%).

The frequency of the dominant allele. Answer: Since q = 0.2, and p + q = 1, then p = 0.8 (80%).

The frequency of heterozygous individuals

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Hope it helps... ¯\_(ツ)_/¯