Chemistry, asked by haresing, 1 year ago


The percentage of water by mass is 54percentage in a mixture of ethanol and water. The mole fraction of water in this solution is .

Answers

Answered by gadakhsanket
9

Hey Dear,

◆ Answer -

Mole fraction of water = 0.75

● Explanation -

Let's take 100 g of this mixture. It contains

W1 = 54 % = 54 g (H2O)

W2 = 100-54 = 46 g (C2H5OH)

No of moles of water -

n1 = W1/M1

n1 = 54/18

n2 = 3 mol

No of moles of ethanol -

n2 = W2/M2

n2 = 46/46

n2 = 1 mol

Mole fraction of water will be calculated as -

X1 = n1 / (n1 + n2)

X1 = 3 / (1 + 3)

X1 = 3/4

X1 = 0.75

Therefore, mole fraction of water in the solution is 0.75 .

Thanks dear...

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