The percentage of water by mass is 54percentage in a mixture of ethanol and water. The mole fraction of water in this solution is .
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Hey Dear,
◆ Answer -
Mole fraction of water = 0.75
● Explanation -
Let's take 100 g of this mixture. It contains
W1 = 54 % = 54 g (H2O)
W2 = 100-54 = 46 g (C2H5OH)
No of moles of water -
n1 = W1/M1
n1 = 54/18
n2 = 3 mol
No of moles of ethanol -
n2 = W2/M2
n2 = 46/46
n2 = 1 mol
Mole fraction of water will be calculated as -
X1 = n1 / (n1 + n2)
X1 = 3 / (1 + 3)
X1 = 3/4
X1 = 0.75
Therefore, mole fraction of water in the solution is 0.75 .
Thanks dear...
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