calculate the no. of mole s of N2 atoms in 3.011*10^20 atoms sample( please give a proper explanation)
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Answered by
1
no of moles = no of atoms ÷ avagadro number
no of moles= 3.011*10^20÷6.023*10^23
no of moles =10^20÷2*10^23
no of moles=0.0005
no of moles= 3.011*10^20÷6.023*10^23
no of moles =10^20÷2*10^23
no of moles=0.0005
john44:
but they are atoms
Answered by
2
here given number of atoms of N2 ,
so , we use formula ,
mole = given number of atoms /Avogadro's constant
mole = 3.011 × 10^20/6.022 × 10^23
= 1/2 × 10^-3
= 5 × 10^-4
we see in one mole N2 = 2mole of atoms
so, total number of mole of N2 = 2× 5 × 10^-4 = 10^-3
so , we use formula ,
mole = given number of atoms /Avogadro's constant
mole = 3.011 × 10^20/6.022 × 10^23
= 1/2 × 10^-3
= 5 × 10^-4
we see in one mole N2 = 2mole of atoms
so, total number of mole of N2 = 2× 5 × 10^-4 = 10^-3
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