Question

calculate the no of molecules of nitrogen gas that occupies the volume 448ml at 273k at 2atm​

Answer 1

Answer:

Pressure= 2 atm

temperature= 273K

volume= 44.8cm

3

=44.* litre

so,By PV=nRT

n=

RT

PV

mole=

0.0821×273

2×44.8

so, no of moles= 3.998=4

hence, 4×6.023×10

23

=24.08×10

23