Calculate the no.of molecules of oxygen gas that occupies a volume of 224ml at 273 k and 3 atm pressure
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N = pv ÷ RT
.n = 3 × 0.224liter ÷ 0.0821 × 273
n= 0.672 ÷ 22.4
n = 0.0299mole
Number of molecules = n × Na
= 0.0299 × 6.02× 10^23
= 0.1804 × 10^23
= 1.804 × 10^22
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.n = 3 × 0.224liter ÷ 0.0821 × 273
n= 0.672 ÷ 22.4
n = 0.0299mole
Number of molecules = n × Na
= 0.0299 × 6.02× 10^23
= 0.1804 × 10^23
= 1.804 × 10^22
Hope it helps you ... Mark as brainlist plz PlzZ plzz
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