Question

calculate the no.of molecules present in 10gr of Caco3?​

Answer 1

Answer:

6.022×10^22 molecules

Explanation:

The molecular weight of CACO3 is 100g

and which 1 mole of it

1 00grams-6.022×10^23 molecules of Caco3

10 gram- X

CROSS MULTIPLY 10× 6.022×10^23/100

THE ANSWER IS 6.022×10^22