calculate the no. of molecules present in 11.5 dm3 of N2 at stp
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Explanation:
Answer: We know that, at standard temperature and pressure, 1 mole of any gas at STP contains 22.4 L of it. Therefore 11.5 liters of hydrogen(H2) is (1/22.4)*11.5 moles = 0.51 moles of hydrogen gas. We know that in 1 mole there is 6.022 × 10^23 molecules.
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The number of molecules of nitrogen present at 11.5 litre of nitrogen in STP is equal to 3.011x10²³ molecules
Explanation:
- According to the avogadro's law every mole of nitrogen occupies a total of 22.4 litre at standard temperature and pressure. Near the volume of the gas is said to be 11.5 litre. Hence it is equal to 0.5 mole.
- One mole of a gas occupies 6.023x10²³ molecules. Hens half mole of a gas will occupy 3.011x10²³ molecules
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