Question

Calculate the no. of moles 1)12.044×10^23 of heli atom. 2)3.011×10^23no. of nitrogen atom.

Answer 1

No. of moles = No.of atoms/Avagadro number 
= 12.044×10^23/6.022×10^23
= 2 moles
I)1 mole of atoms = 6.022× 10 ^23 atoms
so
6.022x10^23 atoms = 1 mole
1 atoms = 1/6.022×10^23 mole
3.011x10^23 atoms =
=3.011 ×10^23/6.022×10^23
=1/2 mole
and we also know that ....
1 mole of atom = atomic weight
so.
1 mole of nitrogen.= 14 grams
1/2 mole of nitrogen = 1/2x 14 =7grams
so..mass of nitrogen atom = 7grams

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