Question

calculate
the no. of moles and molecules present in
35.15 gm of uria Also find the no. of
Hydrogen atom present in it​

Answer 1

Answer:

No. of moles = 35.15/60 = 0.58 mole

No. of molecules = 0.58 * 6.022 * 10^23 = 3.5 * 10^23 molecules

No. of H atoms = 0.58 * 6.022 * 10^23 * 4

= 13.96 * 10^23

= 1.4 * 10^24 atoms