Question

The following numbers k+3,k+2,3k-7,2k-3 are in proportion find k

Answer 1

Answer:

Here, (K + 3/K + 2) = (3k - 7/2k - 3) ⇒ (K + 3) (2K – 3) = (K + 2) (3K – 7). ⇒ 2K2 – 3K + 6K – 9 = 3K2 – 7K + 6K – 14 ⇒ K2 – 4K – 5 = 0 ⇒ (K – 5) (K + 1) = 0 ⇒ K = 5 or K