Question

Calculate the no. of moles in 6 x 10^21 NH3, 5 x 10^21 C-atoms and 6.023x10^11 N-atoms.

Answer 1

no. moles of NH3= (6×10^21)/(6×10^23)

=10^-2 or 0.01

no. moles of C = (5×10^21)/(6×10^23)

= 0.83×10^-2

no. of moles of N= (6.023×10^11)/ (6.023×10^23)

= 10^-12