Question

Calculate the no. Of moles of 10.0 g of caco3 by the formula no. Of moles = given no. Of particles / avogadro no.

Expert pls answer this question quickly it's very urgent the answer must be correct i want best answer and don't cheat internet and answer from ncert book and s Chand book the best answer will be marked as brainliest so expert pls answer quickly

Answer 1

BRAINLYY HERE TO HELP !!!

ANSWER
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Relative Atomic Masses :
Calcium = 40
Carbon = 12
Oxygen = 16

Molecular Mass of CaCO3
= Relative Atomic Mass (RAM) of Calcium + RAM of Carbon + 3×RAM of Oxygen

= 40 + 12 + 3×16
= 40 + 12 + 48
= 100

There's another formula for calculating no. of moles

No. of moles = Weight taken / Molecular Mass

Here,
Weight taken is 10.0 g

No. of moles = 10 / 100

No. of moles = 1/10 or 0.1 moles

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HOPE IT HELPS :):):):):)

Answer 2

Hello Mate!

Taking weight as W.

No. of moles = ( W in gram )/( W in g/mol )

So, weight in gram = 10 g

Atomic mass of Ca = 40, C = 12 and O = 16 g/mol

The molecular mass of CaCO3 = ( 40 + 12 + 16 × 3 ) g/mol

= 100 g/mol

So, number of moles = 10g / 100g/mol

= 0.1 mole.

Hence required answer is 0.1 mole.

Have great future ahead!