Question

Calculate the no.of moles of 5.0L of 0.75 M Na2CO3

Answer 1

Molarity- No. of moles of solute/ volume of solution in litre.

Here,

Molarity = 0.5M

Volume of solution = 100ml

Molecular mass of Na2CO3 = 23*2+12+16*3= 106

Using formula and subsituting value we have,

0.5= x*1000/106*100

x= 0.5*106*100/1000

x= 5.3gram

OR

If we convert ME to LITRE then

100ml= 0.1 litre

Mass=moles*molecular mass

= (0.1litre*0.5moles/ litre)*106g

MASS = 5.3GRAMS..

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Answer 2

$molarity = \frac{no. \: of \: moles \: of \: solute}{vol. \: of \: 001 \: in \: litre} \\ vol = 5 \: l \\ m = 0.75 \\ no. \: of \: moles \: = \: 5 \times 0.75 = 3.75 \: m..$

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