Question

calculate the no. of moles of NAOH present in 5 kg of 0.5 m aq. sol.of it

Answer 1

m= 0.5
Molar mass= 23+16+1
= 40g
n= m/M
n= 0.5/40
n=0.0125

Answer 2

m=n/M

0.5=n/40

n=20

thats the answer