Question

calculate the no.of moles of O2 required to produce 240g of mgo by burning mg metal.​

Answer 1

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2Mg + O2 —› 2MgO

Weight of MgO in Normal reaction

2(24g+16g)

80g

According to the question we need to find out number of moles of Oxygen

Moles of MgO in 240g= 240/40=6moles

number of moles of oxygen

1mole oxygen —› 2mole MgO

6mole MgO —› 3mole Oxygen

ans=3 mole

Hope it help you

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