calculate the no. of moles present in 9g of ethane
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Answered by
20
no.of moles=weight/Gran molecular weight
9/30=3/10=0.3 moles
9/30=3/10=0.3 moles
gellisurabhi:
sorry for wrong ans at first
now the ans is0.3 moles only
see as i had posted the right ans by editing
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Answered by
31
Hey mate!
Here's ur answer :
Ethane is a 2-carbon alkane with 6 hydrogens. Molar mass of ethane is 2(molar mass of carbon) + 6(molar mass of hydrogen). Mm = 2(12) +6(1) = 30 g/gmol. Moles of ethane in 9 g is equal to 9g/(30 g/gmol)=.3 gmol C2H6.
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Here's ur answer :
Ethane is a 2-carbon alkane with 6 hydrogens. Molar mass of ethane is 2(molar mass of carbon) + 6(molar mass of hydrogen). Mm = 2(12) +6(1) = 30 g/gmol. Moles of ethane in 9 g is equal to 9g/(30 g/gmol)=.3 gmol C2H6.
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