Question

Calculate the no. Of particles in 31g of p4 molecule

Answer 1

Answer:

no. of particles = no. of moles × 6.0 × 10²³

no. of moles = Mass / Molecular mass

                     = 31 / 124

                     = 0.25

no. of particles = 0.25 × 6 × 10²³

                         = 1.5 × 10²³

Answer 2

The number of particles in 31 g of $P_{4}$ molecule are $1.5 \times 10^{23}$.

Explanation:

According to Avogadro's number, every 1 mole of a substance contains $6.022 \times 10^{23}$ atoms or particles.

It is known that molar mass of $P_{4}$ is 123.90 g/mol and its mass is given as 31 g. Therefore, calculate number of moles of

            No. of moles = $\frac{\text{mass}}{\text{molar mass}}$

                                  = $\frac{31 g}{123.90 g/mol}$

                                  = 0.25 mol

Hence, number of particles present in 0.25 mol of $P_{4}$ are as follows.

                    $0.25 \times 6.022 \times 10^{23}$

                  = $1.5 \times 10^{23}$ particles

Therefore, the number of particles in 31 g of $P_{4}$ molecule are $1.5 \times 10^{23}$.

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