calculate the no. of particles in each of the following. (i) 46g of sodium atom. (ii) 8g of oxygen. (iii) 0.1 mole of oxygen
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i) atomic mass of Na=23u
Number of atoms=Number of Moles x N
⇒(given weight/ Gram atomic weight) x 6.023 x 10²³
=(46/23)x 6.023 x 10²³
=2x 6.023 x 10²³
⇒12.046 x 10 ²³Na particles
∴46 g of Na contains 12.044 x 10 ²³ atoms
ii) Answer is in the pic
iii) 1 Mole of C = 12 grams = 6.023 X 10 23atoms
0.1 Moles of C = 0.1 X 6.023 X 10 23atoms
= 6.023 X 10 22atoms
Therefore 0.1 moles of Carbon contain 6.023 X 10 22atoms
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