Question

Calculate the no. Of particles present in 56 g of nitrogen molecule.

Answer 1

$\huge\pink{As-Salamu-Alykum}$

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$\huge\green{Given:-}$

Mass of N2 = 56g

Molar mass of N2 = 14×2=28g/mol

$\huge\orange{Required:-}$

Number of particles =?

$\huge\red{Formula:- }$

Moles of N2 = no. of particles /Avagadro number

$\huge\purple{Solution:-}$

Moles of N2 = mass / molar mass

Moles of N2 = 56 / 28

Moles of N2 = 2 mol

Now.......

Moles of N2 = number of particles / Avagadro number

Number of particles = Moles of N2 × Avagadro number

Number of particles = 2 × 6.023 ×10^23

$\huge\violet{Number of particles of N2 = 12.04 × 10^23}$

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