Calculate the no. of proton in 340gm H2s
Answers
Answered by
0
Explanation:
1 mole of H2S=6.023 x 10²³ atoms
35(2+33) g of H2S=6.023 X 10²³atoms
1g= 6.023 X 10²³atoms/35
340g=(6.023 X 10²³atoms/35) x 340
In one H2S atom containing 18 no. of proton that is (2+16)
in 340g the no. of protons is (6.023 X 10²³atoms/35) x 340 x18.
Similar questions