Question

calculate the no. of unit cells present in 2g of gold (Au=197)​

Answer 1

Molar mass of gold =197

No. Of atoms in 2g of gold

2/197*6.022*10^23

=6.1137*10^21

As the FCC contains 4 atoms

Unit cell=6.1137/4=1.528*10^21

Hence it contains 1.528*10²¹