Question

Calculate the normality containing 31.5 gm containing hydrate oxalic acid h2c2o4.2h2o in 1250 ml of solution

Answer 1

Answer: 0.4 N

Explanation: Normality of a solution is defined as the number of gram equivalents of solute dissolved per Liter of the solution.

$Normality=\frac{number of gram equivalents\times 1000}{\text {Volume in ml}}$

$Normality=\frac{n\times 1000}{V_s}$

where,

n= gram equivalents of solute

Equivalent mass=${\text {Molecular mass}}{basicity}=\frac{126}{2}=63$

$gram equivalents=\frac{\text{Given mass}}{\text{Equivalent mass}}=\frac{31.5g}{63g/mol}=0.5gramequivalents$  

$V_s$ = volume of solution in ml= 1250 ml

$Normality=\frac{0.5\times 1000}{1250ml}$

$Normality=0.4N$

Answer 2

Answer :

Normality of a solution is defined as the number of gram equivalents of solute dissolved per Liter of the solution.