Question

calculate the number a of particle in 46 g of Na atoms ( atomic mass of na =23u)

Answer 1

atomic mass of sodium = 23 g

no. of moles present in 49 g of Na = given mass / molecular mass

= 46 / 23

= 2

according to avogaderos principal number of particles in 1 mole of Na is 6.022 × 10 ^ 23

so in 2 moles of Na

2 × 6. 022 × 10 ^23

= 12.044 × 10^23

Answer 2

n = m/M
= 46/23
= 2
n = no. of particles/Avogadro’s number
2* 6.022* 10^23 = no. of particles