calculate the number of aluminium ions present in 0.051 g of aluminium oxide(atomic mass of aluminium=27u)
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Answer:
For Helium,
Number of atoms=Number of moles ×6.022×10
23
No of Moles =
6.022×10
23
12.044×10
23
= 2.
Now, atomic mass of He=4
Weight = 2×4 = 8 g
Explanation:
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