Question

calculate the number of aluminium ions present in 0.951g of aluminium oxide.

Answer 1

1244.244 g / cm³

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Answer 2

Molecular formula of aluminum oxide is Al2O3.

• number of ions presents in one molecule of aluminum oxide = 2.

1 gram molecule ( 1 mole ) of Al2O3

= 2 × gram atomic mass of Al +3 × gram atomic mass of O.

= 2× 27 g + 3 ×16 g

= 54 g + 48 g = 102 g .

• 1 gram molecule ( 1 mole ) of Al2O3 contains aluminum ions.

= 2 × 6.022 × 10²³.

= 12. 004 × 10²³

• 102 g of Al2O3 has number of aluminum ions = 12.044 ×10²³

Therefore 0.051g of Al2O3 has number of aluminum ions.

= 12.044× 10²³× 0.051/ 102

= 6.022 × 10²⁰ ions.

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