Question

Calculate the number of aprticles in each of the following.
[a] 46gm of Na
[b] 8 gm of O↓²
[c] 0.1 mole of hydrogen

No spam

Explanation required
​

Answer 1

Use unitary method to solve these problems easily...

Explanation:

No. of particles in 23g of Na= 6.022*10^23

No. of particles in 46g of Na=x

= X =6.022 *10^23 *46/23

= x = 12.044*10^23 = 1.2044*10^24(ans)

No. of particles in 32 g of O2= 6.022*10^23

=8g of O2 = 6.022*10^23 *8/32

=1.505*10^23(ans)

1 mole of hydrogen = 6.022*10^23

=0.1 mole=6.022*10^23*0.1

=6.022*10^22(ans)

Answer 2

Answer:

answer=6.022×10^22 is answer