Calculate the number of aprticles in each of the following.
[a] 46gm of Na
[b] 8 gm of O↓²
[c] 0.1 mole of hydrogen
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Answered by
1
Use unitary method to solve these problems easily...
Explanation:
No. of particles in 23g of Na= 6.022*10^23
No. of particles in 46g of Na=x
= X =6.022 *10^23 *46/23
= x = 12.044*10^23 = 1.2044*10^24(ans)
No. of particles in 32 g of O2= 6.022*10^23
=8g of O2 = 6.022*10^23 *8/32
=1.505*10^23(ans)
1 mole of hydrogen = 6.022*10^23
=0.1 mole=6.022*10^23*0.1
=6.022*10^22(ans)
Answered by
0
Answer:
answer=6.022×10^22 is answer
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