Calculate the number of atom in(a) 52u of helium (b) 52 g of helium
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4 u of Helium (He) = 1 atoms of He
52 u of He = 1/4x 52 = 13 atoms
4 g of He contains = 6.023 x 10−2310−23 atoms
52 g of He contains =6.023 x 10231023 x 52/4= 7.8286 x 10241024 atoms
I HOPE THAT IS IT WHAT YOU WANT
52 u of He = 1/4x 52 = 13 atoms
4 g of He contains = 6.023 x 10−2310−23 atoms
52 g of He contains =6.023 x 10231023 x 52/4= 7.8286 x 10241024 atoms
I HOPE THAT IS IT WHAT YOU WANT
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