calculate the number of atom of carbon in 88 g of carbon dioxide
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Answered by
11
Molar mass of CO2 = 44g/mol
Number of moles of CO2 present in 88g of CO2 = 88g/44g mol-1
= 2 moles
1 mole of CO2 contains 2 moles of Oxygen atoms. Hence 2 moles of CO2contains 4 moles of Oxygen atoms
1 mole of oxygen contains 6.023 X 1023atoms of oxygen
4 moles of oxygen contains = 4 X 6.023 X 1023
= 24.092 X 1023
= 2.4092 X 1024 atoms of oxygen
Therefore 88g of CO2 Contains 2.4092 X 1024 atoms of oxygen
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Number of moles of CO2 present in 88g of CO2 = 88g/44g mol-1
= 2 moles
1 mole of CO2 contains 2 moles of Oxygen atoms. Hence 2 moles of CO2contains 4 moles of Oxygen atoms
1 mole of oxygen contains 6.023 X 1023atoms of oxygen
4 moles of oxygen contains = 4 X 6.023 X 1023
= 24.092 X 1023
= 2.4092 X 1024 atoms of oxygen
Therefore 88g of CO2 Contains 2.4092 X 1024 atoms of oxygen
hope it helps
please mark it as brainlist
Answered by
5
Answer:
Explanation:
molecular mass of CO2=12+32=44
no. of moles =given mass /molar mass
now its simple ,
88/44 =2
no. of moles =2
now the number of atoms of carbon =2 x 6.022 x 10^23
=1.2044 x 10^24 atoms
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