Question

calculate the number of atoms in 125 gram of calcium and 130 gram of iron which one has more number of atoms and how much is the difference given atomic mass of calcium is equals to 40 iron is equal to 56​

Answer 1

40 g of Ca = 1 mol

120 g = 120/40 = 3 mol

1 mol contains 6.022 x 10^23 atoms

Therefore,

3 mol contains 3 x 6.022 x 10^23 Ca atom

= 18.066 x 10^23 Ca atoms

56 g of Fe = 1 mol

120 g of Fe = 120/56 = 2.14 mol

1 mol contains 6.022 x 10^23 atoms

2.14 mol = 2.14 x 6.022 x 10^23 atoms

= 12.887 x 10^23 Fe atoms

Calcium has more no. of atoms.

Difference = 5.179 x 10^23 atoms

Answer 2

Answer:

Answer:40 g of Ca = 1 mol

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol1 mol contains 6.022 x 10^23 atoms

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol1 mol contains 6.022 x 10^23 atomsTherefore,

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol1 mol contains 6.022 x 10^23 atomsTherefore,3 mol contains 3 x 6.022 x 10^23 Ca atom

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol1 mol contains 6.022 x 10^23 atomsTherefore,3 mol contains 3 x 6.022 x 10^23 Ca atom= 18.066 x 10^23 Ca atoms

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol1 mol contains 6.022 x 10^23 atomsTherefore,3 mol contains 3 x 6.022 x 10^23 Ca atom= 18.066 x 10^23 Ca atoms56 g of Fe = 1 mol

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol1 mol contains 6.022 x 10^23 atomsTherefore,3 mol contains 3 x 6.022 x 10^23 Ca atom= 18.066 x 10^23 Ca atoms56 g of Fe = 1 mol120 g of Fe = 120/56 = 2.14 mol

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol1 mol contains 6.022 x 10^23 atomsTherefore,3 mol contains 3 x 6.022 x 10^23 Ca atom= 18.066 x 10^23 Ca atoms56 g of Fe = 1 mol120 g of Fe = 120/56 = 2.14 mol1 mol contains 6.022 x 10^23 atoms

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol1 mol contains 6.022 x 10^23 atomsTherefore,3 mol contains 3 x 6.022 x 10^23 Ca atom= 18.066 x 10^23 Ca atoms56 g of Fe = 1 mol120 g of Fe = 120/56 = 2.14 mol1 mol contains 6.022 x 10^23 atoms2.14 mol = 2.14 x 6.022 x 10^23 atoms

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol1 mol contains 6.022 x 10^23 atomsTherefore,3 mol contains 3 x 6.022 x 10^23 Ca atom= 18.066 x 10^23 Ca atoms56 g of Fe = 1 mol120 g of Fe = 120/56 = 2.14 mol1 mol contains 6.022 x 10^23 atoms2.14 mol = 2.14 x 6.022 x 10^23 atoms= 12.887 x 10^23 Fe atoms

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol1 mol contains 6.022 x 10^23 atomsTherefore,3 mol contains 3 x 6.022 x 10^23 Ca atom= 18.066 x 10^23 Ca atoms56 g of Fe = 1 mol120 g of Fe = 120/56 = 2.14 mol1 mol contains 6.022 x 10^23 atoms2.14 mol = 2.14 x 6.022 x 10^23 atoms= 12.887 x 10^23 Fe atomsCalcium has more no. of atoms.

Answer:40 g of Ca = 1 mol120 g = 120/40 = 3 mol1 mol contains 6.022 x 10^23 atomsTherefore,3 mol contains 3 x 6.022 x 10^23 Ca atom= 18.066 x 10^23 Ca atoms56 g of Fe = 1 mol120 g of Fe = 120/56 = 2.14 mol1 mol contains 6.022 x 10^23 atoms2.14 mol = 2.14 x 6.022 x 10^23 atoms= 12.887 x 10^23 Fe atomsCalcium has more no. of atoms.Difference = 5.179 x 10^23 atoms