Question

calculate the number of atoms in 49g of H2SO4​

Answer 1

Answer:

2.107*10^24

Explanation:

The molecular mass of H2SO4 =(2*1)+32+ (4*16)  =98g

So,98 g of H2SO4 contains 6.023*10^23 molecules…

Therefore,49g of H2SO4 contains 3.011*10^23 molecules…

So no.of atom present =(2+1+4)=7

So…no.of atoms present in 49g of H2SO4

=(7*3.011*10^23)=2.107*10^24

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Answer 2

Ans : 2.1 ×10^24

Explanation: no. of mole = w/ mol wt.

Here , n = 49g / 98 g = 1/2

n = N / Avogadro no.

=> No. of molecules = 6.022×10^23 × 1/2 = 3.011×10^23

No of atoms in 1 molecule of H2so4 = 7

No of atoms in49 g H2so4 = 7× 3.011× 10^23 = 2.1 ×10^24