Question

Calculate the number of atoms in 5.6L of NH3.

Thanks

Answer 1

Given volume :- 5.6L
One mole contain 22.4L
Moles in 5.6L of NH3= 5.6/22.4 =0.25
numbers of molecules =0.25NA
For numbers of atom = multiply the no. of molecule by total no. Atomicity
0.25NA X 4 = NA
Total no. Of atom = NA

Answer 2

Concept:

Ionic bonds hold together compounds, which have two or more atoms, whereas covalent bonds hold together molecules. A molecule can contain just one element, however, the atoms in a compound must also be distinct from one another.

Given:

The volume of NH₃ = 5.6 L

Find:

Calculate the number of atoms in 5.6L of NH₃.

Solution:

We know that,

22.4 L = 1 mole of NH₃

Therefore,

5.6 L = (5.6 L * 1 mol) / 22.4 L

5.6 L = 0.25 mol

1 mol of gas contains 6.023 * 10²³ molecules.

0.25 mol will contain = (0.25 * 6.023 * 10²³) / 1

= 1.5 * 10²³ molecule

So, there are 4 atoms in the ammonia molecule i.e., one atom of nitrogen and 3 atoms of hydrogen.

Thus, the number of atoms in 5.6L of NH3 = 4 * 1.5 * 10²³ atoms

= 6.0 * 10²³ atoms of NH₃

Hence, the number of atoms in 5.6L of NH₃ is 6.0 * 10²³ atoms.

#SPJ2