Question

In a triangle abc right angled at a having a b is equal to 5 cm bc is equal to 12 cm find sin b, cos and tan b

Answer 1

AB = 5 cm

BC = 12 cm

Base = 12 cm

Perpendicular = 5 cm

Hypotenuse = sqrt ( 12^2 + 5^2)

= sqrt (144 + 25)

= sqrt (169)

= 13

Now,

Sin B = P / H = 5 / 13

Cos B = B / H = 12 /13

Tan B = P /B = 5 / 12

Answer 2

AB = 5 cm

BC = 12 cm

Base = 12 cm

Perpendicular = 5 cm

Hypotenuse = sqrt ( 12^2 + 5^2)

= sqrt (144 + 25)

= sqrt (169)

= 13

Now,

Sin B = P / H = 5 / 13

Cos B = B / H = 12 /13

Tan B = P /B = 5 / 12

hope it helped ⚡

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