Question

calculate the number of atoms in 52 g of helium​

Answer 1

Answer:

moles of He = 52 / 4

=13

now.,

no of atoms = moles * Na( avogadro no.)

= 13* 6 * 10^23

= 78*10^23 atoms

Answer 2

hope it hepls....

Explanation:

no of moles of helium = 52/4

= 13

so, no of atoms = 13 * avogadro's no.

= 13 * 6.022 * 10^23