Question

Calculate the number of atoms in 52 gram of helium

Answer 1

Mass of He = 52g

1 mole of He = 6.02 x 10^23 atoms = 2g

Moles of He = Given mass/Molar mass = 52/2 = 26 mol

No. of atoms of He present = 26 x 6.02 x 10^23 = 1.56 x 10^25 atoms