calculate the number of atoms in a cubic based unit cell having one atom on each corner and two atims on each body diagonal.
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contribution of each atom at the corner = 1/8
contribution of each atom at the body = 1
No of atoms = 1 + 1 =2
contribution of each atom at the body = 1
No of atoms = 1 + 1 =2
premkumar17:
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hey friend!!!
=> Contribution of each atom at the corner = 1/8
=> Contribution of each atom at the body = 1
=> No of atoms =1+1=2
hope it will help you..
=> Contribution of each atom at the corner = 1/8
=> Contribution of each atom at the body = 1
=> No of atoms =1+1=2
hope it will help you..
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