Question

sin^2theta-cos^2theta=2sin^2theta-1

Answer 1

LHS = sin²A- cos²A
=sin²A- (1-sin²A)
=2sin²A - 1 = RHS
Where, Theta = A

Answer 2

Hey user here is your answer......

----> L.H.S

◆Sin^2theta -cos^2theta----(1)

◆Sin^2theta + Cos^2theta=1

◆Cos^2theta=1-sin^2theta

◆Put in equation (1)

◆Sin^2theta-(1-sin^2theta)

◆Sin^2theta-1+Sin^2theta

◆2sin^2theta - 1


______Hence proved_________

Hope it helps you☺️