Question

calculate the number of atoms of carbon present in 25gm caco3

Answer 1

Hey

The Atoms of carbon present in caco3 is

$\frac{25}{100} = 0.25 \\ so \: mole \: of \: carbon \: in \: 25gm \: caco3 \: is \: \\ = mole \times 6.022 \times {10}^{23} \\ = 0.25 \times 6.022 \times {10}^{23} \\ = 1.5055 \times {10}^{23}$
Hope it helps you

Answer 2

Hi.
Here is your answer-----
Given----- 
Mass of CaCO3 = 25 g
We know,, Molecular Mass of CaCO3 = 100 grams
Also, mass of carbon present in CaCO3 = 12 grams
Thus,              100 grams of CaCO3 contains 12 grams of carbon  Therefore, 1 grams--------------------------------12/100 grams of carbon
Thus,25 grams------------------------------------------(12/100) x 25 grams of carbon                                                                           = 3 grams of carbon
Thus,answer is 3 grams of carbon.

Number of atoms = (mass/ atomic mass) x avogadro's number
= (3/12) x 6.02 x10^23
= 1.505 x 10^23

Hope this will help u.
Have a nice day.
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