Question

calculate the number of atoms of carbon present in 25gm caco3

Answer 1

the present in 25g of caco3 is 1.5 ×
${ {10}^22$

Answer 2

Given: 25 grams of calcium carbonate.

To find: We have to find the number of carbon atoms.

Solution:

The chemical formula of calcium carbonate is $CaCO_3$.

The atomic mass of Ca is 40, C is 12 and Oxygen is 16.

Thus the molecular mass of calcium carbonate is-

$40 + 12 + 16 \times 3 \\ = 40 + 12 + 48 \\ = 100$

The number of carbon atoms in 1 mole of calcium carbonate is one.

Thus 100g of calcium carbonate contains $6.023×10^{23}$ number of carbon atoms.

Thus 25 g of calcium carbonate contains $6.023×10^{23}×25/100=1.5×10^{23}$ number of carbon atoms.

Thus 25 g of calcium carbonate contains $1.5×10^{23}$ number of carbon atoms.