Question

Calculate the number of atoms of each element present in 50 grams of limestone.
please answer ​

Answer 1

Answer:

50.0 grams of CaCO3=50.0100.0=0.5 gram mol. 0.5 gram mole of CaCO3 contain oxygen atoms =0.5×3×6.022×1023=9.03×1023 atoms.

Answer 2

Answer:

50.0 grams of CaCO3= 50.0100.0= 0.5 gram mol.

0.5 gram mole of CaCO3 contain oxygen atoms.

$= 0.5 \times 3 \times 6.002 \times 1023 = 9.03 \times 1023 atoms.$

Explanation:

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