Calculate the number of atoms of each kind in 5.3 grams of Sodium carbonate
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no of moles in 5.3 grams Na2CO3 are
5.3/106 = 0.05 moles
number of atoms = 0.05 × 6.022 × 10²³
AKSHITH04:
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Answered by
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Molar mass of sodium carbonate = 106u
Mole = given mass / molar mass
= 5.3/106 = 0.05 mole
1mole contains 6.02 × 10^23 atoms
Then no of atom in 0.05 moles = 0.05 × 6.02 × 10^ 23atom
= 3.011 × 10^22 atom
Ans= 3.011 × 10^ 22atom
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