Question

calculate the number of atoms of each type in 53g of Na2CO3?

Answer 1

Molar mass of Na2CO3 is 106 g
So 53 g will be half mole
In 1 mole Na2CO3 there are 2mol Na, 1 mol C, 3 mol O
So in 1/2 mole i.e. 53g Na2CO3 :
Na= 1mol = 6.022*10^23 atoms
C=1/2 mol =3.011*10^23 atoms
O=1.5mol= 9.033*10^23 atoms



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