calculate the number of atoms of each type of 37g cuso4.5h2o (atomic masses cu=63.5u s=32u o=16u h=1u
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the mole of cuso4 is
37/95.5 =0.38
Now in one mole of cuso4 atoms is 6.022 into 10^-21
so in 0.38 how many
0.38 into 6.022 into 10^-21
= 2.33 into 10^21
37/95.5 =0.38
Now in one mole of cuso4 atoms is 6.022 into 10^-21
so in 0.38 how many
0.38 into 6.022 into 10^-21
= 2.33 into 10^21
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