Calculate the number of atoms of the constituent elements in 53 g of na2co3.
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Avagadro's constant states that 1 mole of any substance has 6.022 × 10²³ molecules/atoms.
Find the number of moles of 53 g of Na2CO3:molar mass Na2CO3 = 23 × 2 + 12 + 16 × 3 = (46+12+48) = 106
moles = mass/molar mass = 53/106 = 0.5 moles
1 mole = 6.022 ×10²³ atoms Then 0.5 moles = 6.022 × 10²³ × 0.5 atoms = 3.011 × 10²³ atoms of Na2CO3
Find the number of moles of 53 g of Na2CO3:molar mass Na2CO3 = 23 × 2 + 12 + 16 × 3 = (46+12+48) = 106
moles = mass/molar mass = 53/106 = 0.5 moles
1 mole = 6.022 ×10²³ atoms Then 0.5 moles = 6.022 × 10²³ × 0.5 atoms = 3.011 × 10²³ atoms of Na2CO3
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